Apolynomial has been factored below, but some constants are missing.
3x^3+6x^2-24x=ax(x+b)(x+c)
what are the missing values of a, b, and c

a=3, b=4, and c=-2

Step-by-step explanation:

3x^3+6x^2-24x

Each of the three terms has a common factor of 3x.

3x(x^2+2x-8)

Now can you think of two numbers that multiply to be -8 and add to be 2?

How about 4 and -2? 4(-2)=-8 and 4+(-2)+2.

So the factored form of x^2+2x-8 is (x+4)(x-2).

We can check this by using foil.

First: x(x)=x^2

Outer: x(-2)=-2x

Inner:  4(x)=4x

Last: 4(-2)=-8

Add them up! This gives you x^2+2x-8 which is the desired result.

So the factored form of 3x^3+6x^2-24x is 3x(x+4)(x-2).

Comparing 3x(x+4)(x-2) to ax(x+b)(x+c) gives us  a=3, b=4, and c=-2

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b