Which statement is true about the factorization of 30x2 +40xy+51y2

prime

not factorable over the reals

Step-by-step explanation:

30x^2+40xy+51y^2 is not factorable (also know as prime)

because the discriminant is negative.

That is when I computed b^2-4ac, in this case 40^2-4(30)(51)=-4520.

If the discriminant is negative, then it isn't factorable over the reals.

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.