![\bf 7~~,~~\stackrel{7+6}{13}......601\qquad \qquad \stackrel{\textit{common difference}}{d = 6} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\ \cline{1-1} a_1=7\\ d=6\\ a_n=601 \end{cases} \\\\\\ 601=7+(n-1)6\implies 601=7+6n-6\implies 601=1+6n \\\\\\ 600=6n\implies \cfrac{600}{6}=n\implies 100=n \\\\[-0.35em] ~\dotfill](/tpl/images/0064/2435/a30c8.png)
7 + 13 + . . + 601
a. 182,704
Mathematics, 08.07.2019 04:10 rue61
Find the sum of the series of the arithmetic series:
7 + 13 + . . + 601
a. 182,704
b. 60,800
c. 30,400
d. 15,200
Answers: 2
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You know the right answer?
Find the sum of the series of the arithmetic series:
7 + 13 + . . + 601
a. 182,704
7 + 13 + . . + 601
a. 182,704
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