Which polynomial could have the following graph?
y = (x + 3)(x - 1)(x - 5)
y = (x - 3)(x + 1)(x + 5)
y = -(x + 3)(x - 1)(x - 5)
y = -(x - 3)(x + 1)(x + 5)

y= (x+3) (x-1) (x-5)

Step-by-step explanation:

The graph crosses the x axis at the points -3,1,5

These are also called the zeros

f(x) =k (x-a) (x-b) (x-c)

where a,b,c,... are the zeros of the function and k is a constant

f(x) = k * (x--3) (x-1) (x-5)

f(x) = k(x+3) (x-1) (x-5)

To help determine the value of k

Take another point  at x = 0, we know the value is positive

f(0) = k(3) (-1) (-5)

f(0) = k(15)

That means k must be greater than 0  Looking at the graph, it should be around 1

f(x) = (x+3) (x-1) (x-5)

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.