Twenty percent of all telephones of a certain type are submitted for service while under warranty. of these, 60% can be repaired, whereas the other 40% must be replaced with new units. if a company purchases ten of these telephones, what is the probability that exactly two will end up being replaced under warranty?

Probability that exactly two will end up being replaced under warranty is 0.052.

Step-by-step explanation:

Since we have given that

Probability of all telephones are submitted for service = 20%

Probability of telephones get repaired = 60% of 20% = 0.12

Probability of telephones do not get repaired = 1-0.12 = 0.88

Probability of telephones get replaced = 40% of 20% = 0.80

Number of trials = 10

We need to find the probability that exactly two will end up being replaced under warranty.

We would use "Binomial distribution":

Let X be the number of replaced under warranty.

Hence, Probability that exactly two will end up being replaced under warranty is 0.052.

yo answer should be 6 if im not mistaken

step-by-step explanation:

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: