From a standard 52-card deck, how many eight-card hands consists of three cards of one denomination, three cards of another denomination, and two cards of a third denomination?

Answer with explanation:

Total number of Cards in a Pack of Card =52

There are 13 different denomination in the pack of 52 cards each being 4 in number.

⇒Number of ways of selecting 3 cards out of 4 cards , Since order of choosing of cards is not Important

⇒Number of ways of selecting 2 cards out of 4 cards , Since order of choosing of cards is not Important

Now we have to find eight card hands which consists of three cards of one denomination, three cards of another denomination, and two cards of a third denomination

  =As there are 13 cards of different denomination each being 4 in number,so we will choose one among 13 different denomination, then 12 different denomination of card are left, so then we will chose second denomination out of 12, then out of 11 we will choose third denomination.

Since order of arrangement is not important, if you will choose 2 cards of any denomination first,then three cards of any denomination at second place....you will get the same result.

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

step-by-step explanation:

d would equal 12