Which equation results from taking the square root of both sides of (x -9)2 = 81?
ox-9 = +9
x + 9 = +9
x + 3 = +9
ox-3 = +9

x + 9 = 9, which leads to x = 0

Step-by-step explanation:

Please use " ^ " to indicate exponentiation:  (x -9)^2 = 81.  Also, please use " 0 " for "zero," not O (which is the capitalization of " o ").

Recall that the square root of a square could be either + or -.  Thus,

√(x - 9)² = ±√81.  This results in:

x - 9 = 9 and x - 9 = -9.

In the first case, x = 18 and in the second x = 0.

Two of the four given possible answers have " O " in them.  Discard these.

Doing so leaves us with first x + 9 = 9, which leads to x = 0.  Correct.

... with second x + 3 = 9, which is not correct.

x – 9 = ±9

Step-by-step explanation:

just took it

no problobm

step-by-step explanation:

answer: sine

step-by-step explanation: