How many integers between 1 and , inclusive, are divisible by 3 or
5 or 7?

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) =

n( divisible by 5) =

n( divisible by 7) =

n( divisible by 3 and 5) = n(3∩5)=

n( divisible by 5 and 7) = n(5∩7) =

n( divisible by 3 and 7) = n(3∩7) =

n( divisible by 3,5 and 7) = n(3∩5∩7) =

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

answer: i don't understand. what are the options

step-by-step explanation:

a: 1/6, j: 1/4

step-by-step explanation: you are welcome