The strength of a certain type of rubber is tested by subjecting pieces of the rubber to an abrasion test. for the rubber to be acceptable, the mean weight loss μ must be less than 3.5 mg. a large number of pieces of rubber that were cured in a certain way were subject to the abrasion test. a 95% upper confidence bound for the mean weight loss was computed from these data to be 3.45 mg. someone suggests using these data to test h0 : μ ≥ 3.5 versus h1 : μ < 3.5. it is discovered that the mean of the sample used to compute the confidence bound is

which expression can be used to convert 80 us dollars (usd) to australian dollars (aud)?

1 usd = 1.0343 aud

1 aud = 0.9668 usd

step-by-step explanation:

sorry just need the points

1e+27

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92