Which statement accurately describes how to reflect point a (−2, 1) over the x‐axis?
a. construct a line from a perpendicular to the x-axis, determine the distance from a to the x-axis along this perpendicular line, find a new point on the other side of the x-axis that is equidistant from the x-axis.
b. construct a line from a parallel to the x-axis, determine the distance from a to the x-axis along this parallel line, find a new point on the other side of the x-axis that is equidistant from the x-axis.
c. construct a line from a perpendicular to the y-axis, determine the distance from a to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis.
d. construct a line from a parallel to the y-axis, determine the distance from a to the y-axis along this parallel line, find a new point on the other side of the y-axis that is equidistant from the y-axis.

A. Construct a line from A perpendicular to the x-axis, determine the distance from A to the x-axis along this perpendicular line, find a new point on the other side of the x-axis that is equidistant from the x-axis.

Step-by-step explanation:

The rule for a reflection over the x -axis is (x,y)→(x,−y) . The given point is A(-2,1) .The reflected point will be A'( -2,-1) .

To locate the reflected point A' we draw a perpendicular line from A then we measure the distance from point A to x axis along the perpendicular line drawn .The reflected point A' is constructed on the other side which is equidistant from x axis as was point A.

Option A is the right option.

The Answer is

Step-by-step explanation:

A. Construct a line from A perpendicular to the x-axis, determine the distance from A to the x-axis along this perpendicular line, find a new point on the other side of the x-axis that is equidistant from the x-axis.

probably .5

i can on others if necessary.

do have an equation or graph or

step-by-step explanation: