Mathematics, 01.07.2019 20:20 karen7088
Find the standard form of the equation of the parabola with a focus at (0, -2) and a directrix at y = 2.
Answers: 3
![\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{we'll use this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=0\\ k=0\\ p=-2 \end{cases}\implies 4(-2)(y-0)=(x-0)^2\implies -8y=x^2\implies y=-\cfrac{1}{8}x^2](/tpl/images/0039/9322/68b93.png)
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Find the standard form of the equation of the parabola with a focus at (0, -2) and a directrix at y...
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