Refer to the accompanying data set and use the 30 screw lengths to construct a frequency distribution. begin with a lower class limit of 0.470 in, and use a class width of 0.010 in. the screws were labeled as having a length of 1 divided by 2 in. does the frequency distribution appear to be consistent with the label? why or why not?
screw lengths (inches)
0.478
0.503
0.507
0.478
0.488
0.493
0.508
0.479
0.506
0.502
0.509
0.493
0.495
0.485
0.509
0.505
0.498
0.485
0.497
0.485
0.498
0.515
0.501
0.502
0.497
0.489
0.509
0.491
0.505
0.499
complete the frequency distribution below

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

answer:

it is 28 degrees colder in detroit than philadelphia.

step-by-step explanation:

what number adds to 21  

-7 + ? = 21

-7 + 28 = 21

hope it

the answer that is correct is false