Out of 100 students sampled, 70 of them said that they hoped to get married someday. with 68% confidence, what is the approximate percentage of the students in the population who hope to get married someday?

65.4% to 74.6%

Step-by-step explanation:

68% is approximately plus minus 1 standard deviations.

sigma=sqrt(n*p*(1-p))=sqrt(100*.7*.3)=4.58

so we're looking at  70+4.6 and 70-4.6.

Step-by-step explanation:

Given : Out of 100 students sampled, 70 of them said that they hoped to get married someday.

i.e. Sample size : n= 100 and Sample proportion:

Using standard normal table for z,

Critical z-value(two-tailed) for 68% confidence =

Now, confidence interval for population proportion:-

Hence, the approximate percentage of the students in the population who hope to get married someday =

what is the starting amount? the question is not clear sorry.

step-by-step explanation: