Assume that women's heights are normally distributed with a mean given by mu equals 63.4 in, and a standard deviation given by sigma equals 2.7 in. (a) if 1 woman is randomly selected, find the probability that her height is less than 64 in. (b) if 48 women are randomly selected, find the probability that they have a mean height less than 64 in.

0.9895

Step-by-step explanation:

From the mean to the value of interest:  

63.0

−

62.4

=

0.6

inches

So the count of standard deviations beyond the  

mean of 63 is:  

0.6

2.8

σ

So the all encompassing probability from the left for  

μ

+

6

26

σ

=

0.9895

Used 'Elementary Statistics Tables by Henry R Neave

(if you like, you can add your values to this website http://davidmlane.com/hyperstat/z_table.html)

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

step-by-step explanation:

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75