Suppose that the first goal in a gp problem is to make 3 x1 + 4 x2 approximately equal to 36. using the deviational variables d1- and d1+, the following constraint can be used to express this goal. 3 x1 + 4 x2 + d1- - d1+ = 36. if we obtain a solution where x1 = 6 and x2 = 2, what values do the deviational variables assume?

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation:

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

25/6

step-by-step explanation:

you multiply 4 by the denominator (4*6=24) and add it to the numerator which makes it 25/6.