The factored form of polynomial p(x) shows only two of its roots. assuming all of the
coefficients in the expanded form of p(x) are real, select each number that could be a
missing root of p(x)

C and E

Step-by-step explanation:

Recall that according to the complex conjugate theorem, if P(x) is a polynomial function with real coefficients, and a+bi is an imaginary root of P(x), then its conjugate (i.e a-bi) must also be a root.

Here we see that 2 of the given roots are imaginary : i and 2+i

by the theorem given above, the conjugates of these must also be roots

i.e -i and 2-i

mxb67

step-by-step explanation:

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled