Kari and samantha have determined that their water-balloon launcher works best when they launch the balloon at an angle within 3 degrees of 45 degrees. which equation can be used to determine the minimum and maximum optimal angles of launch, and what is the minimum angle that is still optimal? |x – 3| = 45; minimum angle: 42 degrees |x – 3| = 45; minimum angle: 45 degrees |x – 45| = 3; minimum angle: 42 degrees |x – 45| = 3; minimum angle: 45 degrees

  |x – 45| = 3; minimum angle: 42 degrees

Step-by-step explanation:

The difference between x and 45 degrees can be written ...

  x -45

You want the magnitude of that to be equal to 3 degrees at the limits:

  |x -45| = 3

The two solutions to this equation are x ∈ {42, 48}. The smallest angle is then 42 degrees.

|x - 45| = 3; minimum angle: 42 degrees

Step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.