Sone for x and y
2x -y = 11
3x – 2y=6
select one
a. (16.-21)
b. (4, -3)
c. (-3,4)
d. (16,21)

d

Step-by-step explanation:

Given the 2 equations

2x - y = 11 → (1)

3x - 2y = 6 → (2)

Multiply (1) by - 2 and adding will eliminate y

- 4x + 2y = - 22 → (3)

Add (2) and (3) term by term

(3x - 4x) + (- 2y + 2y) = (6 - 22)

- x = - 16 ( multiply both sides by - 1 )

x = 16

Substitute x = 16 into (1) or (2) for corresponding value of y

(1) : 32 - y = 11 ( subtract 32 from both sides )

- y = - 21 ( multiply both sides by - 1 )

y = 21

Solution is (16, 21 ) → d

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

his chances of getting a coin of higher value is 4/19

step-by-step explanation: