The area of the indoor sports exhibition is shown below.
what is its perimeter?
m
what is its area?

Step-by-step explanation:

The perimeter of the circular part of the sports exhibition can be found with the formula r.The equation is halved from the 2r as it is half a circle.

perimeter of circular part=17

Perimeter of the sports exhibition:

(4000/100)+10+10+68+33+17+34+(700/100)

=202+17

=255m(nearest whole number)

For the area, find the total area of the representive shapes

The two rectangles:10*40+68*33

=2644

The area of the semi circle (:r^2)/2

=17*17*/2

=144.5

Total area:

2644+144.5

=3098m^2(nearest whole number)

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14

hope this .

r3t40