Is the expression 2f + 4f + 2 – 3 equivalent to 6f – 1?

6f – 1 evaluated at f = 9 is 53.

2f + 4f + 2 – 3 evaluated at f = 9 is also 53.

6f – 1 evaluated at f = 3 is 17.

what is 2f + 4f + 2 – 3 evaluated at f = 3?

iv been stuck for 10 min now

Yes it is equivalent.

Step-by-step explanation:

In this case the only thing that you have to do to know if the two expressions are equivalent are put them on opposite sides of the equation like this:

6f-1= 2f+4f+2-3

When you simplify this you´ll end up with the next equation:

6f-1= 6f -1

In this case you can see that both expressions are equivalent because they are the same once you put them on opposite sides of the equation.

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.