I'll give you the brainliest! a random sample of 3000 people was chosen for a survey. 47% of them had children under 18 living at home. find the 95% confidence interval - see picture

0.4521 - 0.4879

Step-by-step explanation:

1) Find the standard deviation with the given information:

n=3000

p=47% ⇒ 0.47

1-p= 1 - 0.47 = 0.53

2) Find the margin of error (ME) with the given information:

C=95% ⇒ Z = 1.960

σ=0.009112

ME = Z × σ

= 1.96 (0.009112)

= 0.01786

3) Find the confidence interval with the given information:

p = 0.47

ME = 0.01786

CI = p ± ME

= 0.47 ± 0.01786

= (0.4521, 0.4879)

i believe the correct answer is option 4.principalities were small territories that were run by russian rulers.

which statement correctly defines principalities in northern asia in the 1200s? principalities were small territories that were run by russian rulers.

hope i could ! : )