Michael has never taken a foreign language class, but is doing a story on them for the school newspaper. the school offers french and spanish. michael has a list of all 25 kids in the school enrolled in at least one foreign language class. he also knows that 18 kids are in the french class and 21 kids are in the spanish class. if michael chooses two kids at random off his list and interviews them, what is the probability that he will be able to write something about both the french and spanish classes after he is finished with the interviews? express your answer as a fraction in simplest form.

112/125

Step-by-step explanation:

If we know all 25 are in at least one foreign language class then we can assume that exactly 4 of the 18 kids in French only take French to add up to 25 and this means that the 14 left take both classes. Now we can create three fractions for each case which are 7/25 (Spanish only) 4/25 (French only) and 14/25 (Both) and we can know say that if he goes down the route of getting a Spanish only as his first he needs one of the 18 other students the chances of this happening are 7/25 * 18/25 = 126/625 the same thing is done with the French only and we get 4/25 * 21/25 = 84/625 and then we have the possibility of just getting a student that does both which is 14/25 or 350/625. now we add them all together to get 560/625 which is simplified to 112/125.

Hope this helps please mark brainliest :)

what are the statments

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.