Mathematics, 21.06.2019 15:30 Leggett3146

On the first of each month, shelly runs a 5k race. she keeps track of her times to track her progress. her time in minutes is recorded in the table: jan 40.55 july 35.38 feb 41.51 aug 37.48 mar 42.01 sept 40.87 apr 38.76 oct 48.32 may 36.32 nov 41.59 june 34.28 dec 42.71 determine the difference between the mean of the data, including the outlier and excluding the outlier. round to the hundredths place. 39.98 39.22 0.76 1.21

Answers: 1

Show answers

Answers

Answer from: eksdeeexe

C . 0.76

Step-by-step explanation:

We are given that on the first of each month , Shelly runs a 5 k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:

Jan 40.55 Feb 41.51

March 42.01 Apr 38.76

May 36.32 June 34.28

July 35.38 Aug 37.48

Sept 40.87 Oct 48.32

Nov 41.59 Dec 42.71

We have to find the difference between the mean of the data , including the outlier and excluding the outlier

Outlier: That observation which is different from other observations.

The outlier in the given observations is 48.32 because is different from other observations.

Mean of the data including the outlier

Mean = $\frac{Sum \;of\;observations}{Total\;number\;of\;observations}$

Mean= $\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+48.32+41.59+42.71}{12}$

Mean= $\frac{479.78}{12}$

Mean=39.982

Mean of the data excluding the outlier

Mean= $\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+41.59+42.71}{11}Mean=[tex]\frac{431.46}{11}$

Mean=39.224

Difference between mean of the data including the outlier and excluding the outlier=39.982-39.224=0.758

Difference between mean of the data including the outlier and excluding the outlier=0.76

Answer

Step-by-step explanation:

We are given that on the first of each month , Shelly runs a 5 k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:

Jan 40.55 Feb 41.51

March 42.01 Apr 38.76

May 36.32 June 34.28

July 35.38 Aug 37.48

Sept 40.87 Oct 48.32

Nov 41.59 Dec 42.71

We have to find the difference between the mean of the data , including the outlier and excluding the outlier

Outlier: That observation which is different from other observations.

The outlier in the given observations is 48.32 because is different from other observations.

Mean of the data including the outlier

Mean = $\frac{Sum \;of\;observations}{Total\;number\;of\;observations}$

Mean= $\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+48.32+41.59+42.71}{12}$

Mean= $\frac{479.78}{12}$

Mean=39.982

Mean of the data excluding the outlier

Mean= $\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+41.59+42.71}{11}Mean=[tex]\frac{431.46}{11}$

Mean=39.224

Difference between mean of the data including the outlier and excluding the outlier=39.982-39.224=0.758

Difference between mean of the data including the outlier and excluding the outlier=0.76

Answer :C . 0.76

Answer from: alexj29227405

0.76

Step-by-step explanation:

The mean of the data including the outlier is:

Mean = (40.55 + 41.51 + 42.01 + 38.76 + 36.32 + 34.28 + 35.38 + 37.48 + 40.87 + 48.32 + 41.59 + 42.71)/12 = 39.98 seconds.

In this case, the outlier comes to be the data: 48.32. If we don't consider that data point, the mean equals:

Mean = (40.55 + 41.51 + 42.01 + 38.76 + 36.32 + 34.28 + 35.38 + 37.48 + 40.87 + 41.59 + 42.71)/11 = 39.22

The difference is: 39.98 - 39.22 = 0.76

Answer from: Quest

step-by-step explanation:

Answer from: Quest

yes

step-by-step explanation:

Another question on Mathematics

Mathematics, 21.06.2019 14:30

Factor. 8x2y2 – 4x2y – 12xy 4(8x2y2 – x – 12xy) 4(2xy – 4x2y – 12xy) 4x2y2(2xy – xy –3) 4xy(2xy – x – 3)

Answers: 2

Answer

Mathematics, 21.06.2019 18:50

Which expression shows the sum of the polynomials with like terms grouped together

Answers: 2

Answer

Mathematics, 21.06.2019 23:30

Zach spent 2/3 hour reading on friday a 11/3 hlurs reading on saturday. how much more time did he read on saturday tha on friday

Answers: 1

Answer

Mathematics, 22.06.2019 00:20

Given: jk ||lm prove: _2 = 27 statement justification 1. jk ||lm 1. given 2.26 = 27 3.22 = 26 2. 3. 4. _2 = 27 4. corresponding angles theorem transitive property of equality vertical angles theorem substitution property of equality

Answers: 1

Answer

You know the right answer?

On the first of each month, shelly runs a 5k race. she keeps track of her times to track her progres...

Questions