Which of the following shows the graph of y=2e^x?

The third one.

Step-by-step explanation:

When x=0, the function y=2e^x equals:

y=2e^x = 2e^(0) = 2.

For that reason, the graph should cross the y-axis at the point (0, 2). The only graph that meets this requirement is the third one :).

For this case we must indicate the graph corresponding to the following equation:

Then, we evaluate the equation for

We have by definition, any number raised to zero results in 1.

So:

Now we evaluate the equation for x = -1

We already have two points to graph:

Observing the options, we realize that the correct option is option C.

It should be noted that graphs A and D, by definition, do not correspond to the exponential function.

Option C

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.