1/3x^2+2 what does the graph look like

The answer in the procedure

Step-by-step explanation:

we have

This is a vertical parabola open upward with the the vertex at (0,2)

The vertex is a minimum

The y-intercept is the point (0,2) (value of y when the value of x is equal to zero)

The graph does not have x-intercepts, therefore the solutions of the quadratic equation are complex number

using a graphing tool

see the attached figure

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length