Which absolute value function, when graphed, will be narrower than the graph of the parent function, f(x) = |x|? f(x) = |x| – 3 f(x) = |x + 2| f(x) = 0.5|x| f(x) = 4|x|

f(x) = 4|x|

Step-by-step explanation:

the graph of f(x) = |x|, looks like a "V"

if we want to make the graph "narrower", what we are doing is really trying to make the slope steeper (i.e more vertical) so that the opening of graph at the top of the "V" becomes smaller.

in order the make the slope steeper, we have to multiply the x-term of the function (in this case |x|) by any factor that is greater than 1. (multiplying by factors smaller than 1 will make the slope more gentle and hence making the "V" wider).

The only choice that shows the original function multiplied by a number that is greater than 1 is f(x) = 4|x|

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

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