How does the graph of y= sec(x-2)+2 comparé to the graph of y= sec(x) ?

The function y= sec(x-2)+2 is shifted two units to the right and 2 units upwards., compared to y=sex(x).

Step-by-step explanation:

To solve this problem we need to know the rules for translation of graphs:

Given the function y = f(x):

In this case, our main function is y=sec(x). And the function y= sec(x-2)+2 is shifted two units to the right and 2 units upwards.

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9