Acash register contains 10$ bills and 20$ bills total value of 340 if there are 23 bills total then how many of each does the register contains

There are 12 bills of 10$ and 11 bills of 20$

Step-by-step explanation:

Let

x > number of 10$ bills

y > number of 20$ bills

we know that

x+y=23 > x=23-y > equation A

10x+20y=340 > equation B

substitute equation A in equation B and solve for y

10(23-y)+20y=340

230-10y+20y=340

10y=340-230

y=110/10=11

Find the value of x

x=23-y > x=23-11=12

therefore

There are 12 bills of 10$ and 11 bills of 20$

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75

answer: 12

step-by-step explanation:

because yes