If n is a natural number, then the largest number dividing ( n^3-n ) is a) 2 b) 3 c) 6 d) 12

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

i believe the correct answer is b.

can you put the picture up?

step-by-step explanation: