The length of one of the legs in a right triangle is 3 inches . if the hypotenuse is 10 inches long what the length of the other leg

9.5 inches

Step-by-step explanation:

We are given that in a right angled triangle, one leg is 3 inches long while the hypotenuse is 10 inches long. We are to find the length of the other leg.

For this, we will use the Pythagoras Theorem.

Assuming x to be the length of the other leg.

x = 9.5

9.53 inches

Step-by-step explanation:

In a right  angles triangle, the sum of the squares of the two legs (a and b) equals the square of the the hypotenuse.

a²+b²=c²

Substituting for the values provided in the question we get the following:

3²+b²=10²

b²=10²-3²

b²=91

b=9.53 inches.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752