Rationalize the denominator and simplify. square root of 2/5

√10

  5

Step-by-step explanation:

√(2/5) has a radical in the denominator.  We want to eliminate that radical.  To do this, multiply both √2 and √5 by √5:

√2·√5

    5

This simplifies to

√10

  5

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐