Agroup of 8 trends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. how many different combinations of 5 friends could possibly receive the tickets?

Given that there are 8 friends (5 girls and 3 boys). We have to select only 5 of them. Those 5 can be girl or boy or combination of both because no such restriction is given.

The options in this case are

All five girls go + 4 girls and 1 boy +3 girls , 2 boys+2 girls , three boys

5C5+ (5C4 * 3C1) + (5C3*3C2) + (5C2*3C3)

=1+5*3 + 10*3 +10*1 = 1+15+30+10 = 56

So the answer would be 56

If thats what your talking about.

Hopefully I was help to you!! <3

x-3y=4

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