Find the coordinates of the center of the following circle. (x - 3)² + (y - 7)² = 49 (3, 7) (-3, 7) (-3, -7)

(3, 7).

Step-by-step explanation:

The general form of a circle is:

(x - a)^2 + (y - b)^2 = r^2 where the center is the point (a, b).

So comparing the given equation:

(x - 3)² + (y - 7)² = 49

we see that the center is (3, 7).

(3, 7 )

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 3)² + (y - 7)² = 49 ← is in standard form

with (h, k) = (3, 7) ← centre

i will take them

step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}