1. find the product (13 – x2)(x + 2). -x3 - 2x2 + 13x + 26

The product is -x³ - 2x² + 13x + 26

Step-by-step explanation:

* Lets revise how to find the product of two binomials

- If (ax ± b) and (cx ± d) are two binomials, where a , b , c , d are constant

 their product is:

# Multiply (ax) by (cx) ⇒ 1st term in the 1st binomial and 1st term in the

  2nd binomial

# Multiply (ax) by (d) ⇒ 1st term in 1st binomial and 2nd term in

  2nd binomial

# Multiply (b) by (cx) ⇒ 2nd term in 1st binomial and 1st term in

  2nd binomial

# Multiply (b) by (d) ⇒ 2nd term in 1st binomial and 2nd term in

  2nd binomial

# (ax ± b)(cx ± d) = cx² ± adx ± bcx ± bd

- Add the terms adx and bcx because they are like terms

* Now lets solve the problem

- There are two binomials (13 - x²) and (x + 2)

- We can find their product by the way above

∵ (13)(x) = 13x ⇒ 1st term in the 1st binomial and 1st term in the

  2nd binomial

∵ (13)(2) = 26 ⇒ 1st term in 1st binomial and 2nd term in

  2nd binomial

∵ (-x²)(x) = -x³ ⇒ 2nd term in 1st binomial and 1st term in

  2nd binomial

∵ (-x²)(2) = -2x² ⇒ 2nd term in 1st binomial and 2nd term in

  2nd binomial

∴ The product of (13 - x²)(x + 2) = 13x + 26 - x³ - 2x²

- There is no like terms

- Lets arrange the terms from greatest power to smallest power

∴ The product is -x³ - 2x² + 13x + 26

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )