Iam confused on numbers 25 and 29, the instructions are at the top.

Pretty sure you already had something posted about this... in case you've lost it, or have questions:

#25 is fairly simple.  Plug in -4 and 3 into the equation, and the extraneous root will be the one that does not work.

Extraneous root in this case is positive four since +4≠-4

In this case it's negative 3, since -3≠3

#29 can be turned into a quadratic equation.

Square both sides to get

Then bring the 2x+3 to the other side, setting the quadratic equal to zero.

Factor to find that it's equivalent to
(x-3)(x+1)=0
Therefore x is equal to positive 3 and negative 1.  Plug both back into the original equation.  Whichever does not work is the extraneous root, and the answer is the one that does.



Extraneous root would be negative 3.



Extraneous root would be positive 1.

Your answers are positive 3 and negative 1.
Extraneous roots are negative 3 and positive 1.

Where are the pictures to understand this question? we can’t you if you don’t show the graphs.