In δpqr, sin r = . what is cos p? (a) (b) (c) (d) (image attached below)

Since we know that ΔPQR is a right triangle, we can also asume that:

sin R = cos P = 3/5

So the answer is (d).

* This formular can also be applied to other right triangles.

In a right triangle, sine of one acute angle will always be equal to cosine of the other acute angle.

And we can check this by actually finding cos P using the lengths of the sides, by calculating PR first:

PR = √(PQ² + RQ²) = √(12² + 16²) = 20

=> cos P = PQ/PR = 12/20 = 3/5

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step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)