Mathematics, 23.06.2019 23:30 tdyson3p6xvtu
What is the equation of a parabola with (−2, 4) as its focus and y = 6 as its directrix? enter the equation in the box.
Answers: 1
![\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{we'll use this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-2\\ k=5\\ p=-1 \end{cases}\implies 4(-1)(y-5)=[x-(-2)]^2\implies -4(y-5)=(x+2)^2 \\\\\\ y-5=-\cfrac{1}{4}(x+2)^2\implies y=-\cfrac{1}{4}(x+2)^2+5](/tpl/images/0009/6939/9baf7.png)
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What is the equation of a parabola with (−2, 4) as its focus and y = 6 as its directrix? enter the...
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