![\[\frac{x}{x^{2} +3x+2} -\frac{1}{(x+2)(x+1)} =\frac{x}{x^2+3x+2} -\frac{1}{x(x+1)+2(x+1)} =\frac{x}{x^{2}+3x+2 } -\frac{1}{x^{2} +2x+x+2} =\frac{x}{x^{2} +3x+2} -\frac{1}{x^{2} +3x+2} =\frac{x-1}{x^{2} +3x+2} \]](/tpl/images/0010/3112/9bfd7.png)
What is the difference? x/x2+3x+2 - 1/(x+ 2)(x+1)
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Mathematics, 24.06.2019 03:10 Falconpride4079
What is the difference? x/x2+3x+2 - 1/(x+ 2)(x+1)
Answers: 1
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