Aspinner has 5 sector's of equal size. the sectors are labeled 1,2,3,4, and 5. the spinner is spun twice. x is the number of times 3 is spun

Because the sectors are of equal size, each sector has the same probability of happening.

So for every number, you have a probability of 0.2 of it appearing.

Because you have three odd numbers, the probability to land on an odd number on each spin is 0.6. You can also say that the probability to not have an odd number is 0.4.

So what is the probability to have 0 odd number in two spins?

What is the probability to have 1 odd number in two spins? You can have one odd number on the first or one odd on the second spin, that is why we add the probabilities.

What is the probability to have 2 odd numbers in two spins?

To verify if we did a good job, we add all the probabilities. We should get 1.

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So to slide your bars, you slide them up to the number I gave you for each case.

Hope this helps!

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

the answer is 0.000652422

but if you ment to ask what is 6131 divided by 4, it is 1532.75.

step-by-step explanation: