The proportions of multiple samples of registered voters who vote are normally distributed with a mean proportion of 0.38 and a standard deviation of 0 0485 what is the probability that a sample chosen at random has a proportion of registered voters who vote between 0,37 and 0.39? use the portion of the standard normal table below to answer the question

0.16

Step-by-step explanation:

I think you meant a standard deviation of 0.0485 and a range of 0.37 to 0.38.

Using a calculator with basic probability and statistic functions results in:

normcdf(0.37,0.39,0.38,0.0485) = 0.16.  This is the desired probability.

0.1632

Step-by-step explanation:

Given : The proportions of multiple samples of registered voters who vote are normally distributed .

Mean proportion :

Standard deviation :

Let x be the random variable that represents the proportion of registered

voters.

To find : The probability that a sample chosen at random has a proportion of registered  voters who vote between 0.37 and 0.39.

We first find z-score corresponds 0.37 and 0.39.

Formula for z-score :

For x= 0.37

For x= 0.39

By using the standard normal table, the required probability will be :_

Hence, the probability that a sample chosen at random has a proportion of registered  voters who vote between 0.37 and 0.39 = 0.1632

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.