The length of a rectangle is 8 mm longer than its width. its perimeter is more than 32 mm. let w equal the width of the rectangle. a. write an expression for the length in terms of the width. b. use expressions for the length and width to write an inequality for the perimeter, on the basis of the given information. c. solve the inequality, clearly indicating the width of the rectangle.

Part A

w = width

L = length

L = w+8 since the length is 8 mm longer than the width

Part B

P = perimeter of rectangle

P = 2*(L+W) = 2L + 2W

We want the perimeter to be more than 32 mm, so we want P to be greater than 32

This means we write P > 32

Replace P with either 2(L+W) or 2L+2W. I'll pick 2L+2W

So we go from

P > 32

to

2L+2W > 32

After this, replace L with W+8 (refer to part A above)

We now have

2(W+8) + 2W > 32

Part C

Let's solve the inequality found in part B to get...

2(w+8) + 2w > 32

2w + 16 + 2w > 32

4w + 16 > 32

4w + 16-16 > 32-16 subtracting 16 from both sides

4w > 16

4w/4 > 16/4 dividing both sides by 4

w > 4

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

explanation:

infrared radiation has wavelength in the range between 700 nm and 1 mm. lets' convert these values into scientific notation, keeping in mind that:

let's start from the lower value, we have:

(we moved the dot two places to the left, so we increased the exponent by 2 units, from -9 to -7)

the higher value is:

so, the range of wavelength of infrared radiation is: