Need some with this equation, me! answer the questions in the table below. show all your work and a. use special right triangles to find the exact height of the triangle. this means that you will not round your answer, leave your answer in radical form. state or show which special right triangle you used. don’t forget to label your answer with appropriate units. b. what is the exact area of ∆bcd? this means that you will not round your answer, leave your answer in radical form. don’t forget to label your final answer. show your work.

a. 12sqrt(3) cm.                                     b. 72sqrt(3) cm squared

Step-by-step explanation:

a. I hope you see this a 30-60-90 triangle

The short side is opposite to 30

The long leg is opposite to 60

The hypotenuse, the longest side, is opposite 90.

So you are given short side which is 12 cm.

The long leg (the height in this case) is short side times square root of 3 so your height is 12sqrt(3) cm.

b. The area of a triangle is .5*base*height.

You have both the base and height now so plug them in:

.5(12)(12sqrt(3)) cm squared

6(12)sqrt(3)  cm squared

72sqrt(3) cm squared

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584