The cost to rend a construction crane is $750 per day plus $250 per hour of use. write an inequality that can be used to find the maximum number of hours, h the crane can be used each day without exceeding $2500 per day.

750 + 250h ≤ 2500

Step-by-step explanation:

First, we must set up an equation. We know that the initial value is $750 per day and the rate is $250 for H, hours. Putting this into an expression, we get

750 + 250h

We also know that the total cost per day cannot exceed $2,500. However, the total cost can reach $2,500. Because the cost can go up to $2,500, the expression 750 + 250h must be less than or greater than $2,500 because although the cost can be cheaper than $2,500, the cost may reach $2,500. It just can't go above it.

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

answer is 270 degrees: -

to convert radians to degrees you multiply by 180/π

9π/ 6 * 180 / π

=   9 * 180 / 6

= 9 * 30

=   270 degrees   answer