Find the derivative in the form dy/dx

dy/dx =

Step-by-step explanation:

* Lets revise some rules for the derivative

- The derivative of ㏑(f(x)) = 1/f(x) × f'(x)

- The derivative of u/v = (vu'-uv')/v²

- The derivative of the constant is 0

* Lets solve the problem

∵ y = ㏑[(4x³ - 7)/(3x^5 + 1)]

- Let u = 4x³ - 7 and v = 3x^5 + 1

∵ u = 4x³ - 7

∴ u' = 4(3)x^(3-1) - 0 = 12x²

∵ v = 3x^5 + 1

∴ v' = 3(5)x^(5-1) + 0 = 15x^4

∵ The derivative of u/v = (vu' - uv')/v²

∴ The derivative of u/v =

∵ The derivative of ㏑(f(x)) = 1/f(x) × f'(x)

∴ dy/dx =

- Simplify by cancel bracket (3x^5 + 1)from the 1st fraction with the

 same bracket in the 2nd fraction

∴ dy/dx =

d. 9

step-by-step explanation:

in the table given in the picture, x is the input of the function and f(x) is the output on the given input. in the given table, it can be read as the value of function at -3 is it's respective value of f(x) which is -9.

as we have to find the value of f(3), we will see that what is the value of output on input 3. we can see in the table that the output value at x=3 is 9.

so, option d is the correct answer ..

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step-by-step explanation: