Part a: if (6^2)^x = 1, what is the value of x? explain your answer. (5 points) part b: if (6^9)^x = 1, what are the possible values of x? explain your answer.

Part A: X=0

Part B: x=0

Step-by-step explanation:

Part A

(6^2)^X = 1

Applying the exponent rule:

So, our equation will become:

We know if f(x) = g(x) then ln(f(x))= ln(g(x))

SO, taking natural logarithm ln on both sides and solving.

We know, Applying the rule,

Part B

(6^9)^x = 1

Applying the exponent rule:

So, our equation will become:

We know if f(x) = g(x) then ln(f(x))= ln(g(x))

SO, taking natural logarithm ln on both sides and solving.

We know, Applying the rule,

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

22

step-by-step explanation:

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