Crickets can jump with a vertical velocity of up to 14 ft/s. which equation models the height of such a jump, in feet, after t seconds

h = 147 - 16t^2.

Step-by-step explanation:

Use the following equation of motion

h = ut + 1/2 gt^2    where  h = height, u = initial velocity , g = acceleration due to gravity and t = the time.

So here we have:

h = 14t + 1/2 * -32 * t^2

h = 14t - 16t^2

Height of jump, s(t) = 14t - 16.09t²

Step-by-step explanation:

We have equation of motion s = ut + 0.5 at².

For the this vertical motion we have

              s = height of jump

              u = initial velocity = 14 ft/s

               t = time

               a = acceleration due to gravity = -32.17 ft/s²

Substituting

                 s = 14 x t + 0.5 x (-32.17) x t²

                 s = 14t - 16.09t²

Height of jump, s(t) = 14t - 16.09t²

table 3 represents a direct variation function. : )