Is the work shown in the simplification below correct? explain. csc(t) sec(t) = 1 cos(t) ÷ 1 sin(t) = 1 cos(t) • sin(t) 1 = 1 sin(t) = tan(t)?

E2020

No, the simplification is not correct.

Cosecant is the reciprocal of sine, not cosine.

Secant is the reciprocal of cosine, not sine.

The given expression simplifies to cot(t).

The work shown in the simplification below is incorrect.

Step-by-step explanation:

To start; we have to know  what csc(t) and sec(t) is.

csc(t) = 1/sin(t)      and    sec(t)= 1/cos(t)

So in the above simplification it was all mixed up, csc(t) was substituted with 1/cos(t) instead of 1/sin(t) and sec(t) was substituted with 1/sin(t) instead of 1/cos(t).

So, we are going to solve it the right way;

csc(t) sec(t) =   ÷  

                   =     ×  

                    =

                    = cot(t)

Therefore csc(t) sec(t) = cot(t)   and not tan(t).

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.