Mathematics, 26.06.2019 05:00 nanda22
Aparallelogram has vertices (5, 0), (3, -3), (-4, -3), and (-2, 0). what is the approximate perimeter of the parallelogram?
Answers: 1
![\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{2}\\ b=\stackrel{opposite}{3}\\ \end{cases} \\\\\\ c=\sqrt{2^2+3^2}\implies c=\sqrt{13} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the parallelogram}}{7+7+\sqrt{13}+\sqrt{13}}\qquad \approx \qquad 21.21](/tpl/images/0018/2659/e0696.png)
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Aparallelogram has vertices (5, 0), (3, -3), (-4, -3), and (-2, 0). what is the approximate perimete...
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