The width, w, of a rectangular swimming pool 9r + 1. the area a of the pool is 90r^6+28r^5+2r^(4 )+ 45r^3+5r^2. what is an expression for the length of the pool?

10r⁵ + 2r⁴ + 5r²

Step-by-step explanation:

A = 90r⁶ + 28r⁵ + 2r⁴ + 45r³ + 5r²

Factor our r²:

A = r² (90r⁴ + 28r³ + 2r² + 45r + 5)

Factor 2r² from the first three terms and 5 from the last two:

A = r² (2r² (45r² + 14r + 1) + 5 (9r + 1))

Factor the trinomial:

A = r² (2r² (5r + 1)(9r + 1) + 5 (9r + 1))

Factor out 9r+1:

A = r² (2r² (5r + 1) + 5) (9r + 1)

Distribute the 2r²:

A = r² (10r³ + 2r² + 5) (9r + 1)

Distribute the r²:

A = (10r⁵ + 2r⁴ + 5r²) (9r + 1)

The area is width times length, and the width is 9r + 1.

WL = (10r⁵ + 2r⁴ + 5r²) (9r + 1)

(9r + 1) L = (10r⁵ + 2r⁴ + 5r²) (9r + 1)

L = 10r⁵ + 2r⁴ + 5r²

The length of the pool is 10r⁵ + 2r⁴ + 5r².

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles