The graph of a linear equation passes through three of these points: (0,5), (2, 2), (3, 1), and (4, -1). the point that the graph does not pass through is

no not all of them.

step-by-step explanation:

some of them have a square base.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2